In a random sample of 1000 students, 80% were in favor of longer hours at the school library. What is the standard error of the sample proportion?
A) 0.013
B) 0.160
C) 0.640.
D) 0.800

Question

Quizplus · Accepted Answer

The standard error of the sample proportion is calculated using the formula $\sqrt{\frac{p(1-p)}{n}}$, where $p$ is the sample proportion (0.80 in this case) and $n$ is the sample size (1000). Plugging in the values, we get $\sqrt{\frac{0.80(1-0.80)}{1000}} = \sqrt{\frac{0.80(0.20)}{1000}} = \sqrt{\frac{0.16}{1000}} = \sqrt{0.00016} = 0.01265$, which rounds to 0.013.

In a Random Sample of 1000 Students, 80% Were in Favor