In an 8-horse race, the number of ways that 3 horses can finish first, second, and third (order matters) is given by
A) $8 \cdot 3$.
B) $8^{3}$.
C) $8 \cdot 7 \cdot 6$
D) $\frac{8 \cdot 7 \cdot 6}{3 \cdot 2 \cdot 1}$

Question

Quizplus · Accepted Answer

This is a permutation problem where order matters. The first place can be taken by any of the 8 horses, the second place by any of the remaining 7, and the third by any of the remaining 6, giving $8 \cdot 7 \cdot 6$ ways.

In an 8-Horse Race, the Number of Ways That 3 8⋅38 \cdot 38⋅3

In an 8-Horse Race, the Number of Ways That 3 $8 \cdot 3$