If $A$ and $B$ are mutually exclusive events with $P(A)=\frac{1}{7}, P(B)=\frac{2}{7}$, then $P(A \cup B)$ equals
A) $\frac{3}{7}$.
B) $\frac{19}{49}$.
C) $\frac{2}{47}$.
D) 0 .

Name: If $A$ and $B$ are mutually exclusive events with $P(A)=\frac{1}{7}, P(B)=\frac{2}{7}$, then $P(A \cup B)$ equals A) $\frac{3}{7}$. B) $\frac{19}{49}$. C) $\frac{2}{47}$. D) 0 .
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Question

Quizplus · Accepted Answer

Since $A$ and $B$ are mutually exclusive, $P(A \cup B) = P(A) + P(B) = \frac{1}{7} + \frac{2}{7} = \frac{3}{7}$.

If AAA And BBB Are Mutually Exclusive Events With P(A)=17,P(B)=27P(A)=\frac{1}{7}, P(B)=\frac{2}{7}P(A)=71​,P(B)=72​ , Then P(A∪B)P(A \cup B)P(A∪B)

If $A$ And $B$ Are Mutually Exclusive Events With $P(A)=\frac{1}{7}, P(B)=\frac{2}{7}$ , Then $P(A \cup B)$