Scores for an exam are normally distributed with a mean of 235 and a standard deviation of 52.Then the cut-off point for the top 30% is 270.

Question

Quizplus · Accepted Answer

To find the cut-off point for the top 30% of scores in a normal distribution, we use the z-score formula and look up the corresponding z-value for the top 30% in a standard normal distribution table. The provided value of 270 does not directly indicate it is the cut-off for the top 30% without calculating or looking up the corresponding percentile for a score of 270 given the mean of 235 and standard deviation of 52.

Scores for an Exam Are Normally Distributed with a Mean