Find the center of the circle $x^{2}+y^{2}+16 x+20 y+155=0$.
A) $(-8,10)$
B) $(-8,-10)$
C) $(8,10)$
D) $(8,-10)$

Name: Find the center of the circle $x^{2}+y^{2}+16 x+20 y+155=0$. A) $(-8,10)$ B) $(-8,-10)$ C) $(8,10)$ D) $(8,-10)$
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Quizplus · Accepted Answer

To find the center of the circle, rewrite the equation in the standard form $(x-h)^2 + (y-k)^2 = r^2$. Completing the square for both $x$ and $y$ terms, we get $(x+8)^2 + (y+10)^2 = 9$. Thus, the center is $(-8, -10)$.

Find the Center of the Circle x2+y2+16x+20y+155=0x^{2}+y^{2}+16 x+20 y+155=0x2+y2+16x+20y+155=0 A) (−8,10)(-8,10)(−8,10)

Find the Center of the Circle $x^{2}+y^{2}+16 x+20 y+155=0$
A) $(-8,10)$