During early cleavage in animal embryos,minimal growth of the embryo is observed,even though rapid cell division is taking place.How might this lack of growth be most easily measured without destroying the embryo?
A) oxygen uptake measurements
B) vital dye uptake measurements
C) measurements of embryo movement
D) counting the number of nuclei in the embryo
Correct Answer:
Verified
Q12: Many amphibian species release their sperm and
Q13: Suppose an antibody to bindin was introduced
Q14: One difference between early development in humans
Q15: In Xenopus embryos,which developmental sequence is correct?
A)neurula,blastula,gastrula,cleavage
B)cleavage,neurula,gastrula,blastula
C)gastrula,neurula,cleavage,blastula
D)cleavage,blastula,gastrula,neurula
E)cleavage,gastrula,blastula,neurula
Q16: Where do you suppose the first microtubules
Q18: During organogenesis,the first organ system to begin
Q19: What happens during gastrulation?
A)The neural tube-precursor of
Q20: What happens during cleavage?
A)The neural tube-precursor of
Q21: Given the relative positions of the three
Q22: A sea urchin egg has a membrane
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