Star A has an apparent magnitude of 5. Star B has an apparent magnitude of 3.

Question

Quizplus · Accepted Answer

The formula for apparent magnitude is m = -2.5 log(L/L0), where m is the apparent magnitude, L is the luminosity of the star, and L0 is the luminosity of the reference star.Star A has an apparent magnitude of 5, so m1 = -2.5 log(L1/L0).Star B has an apparent magnitude of 3, so m2 = -2.5 log(L2/L0).Dividing the first equation by the second equation, we get:m1/m2 = (L1/L0)/(L2/L0)m1/m2 = L1/L2Substituting the given values, we get:5/3 = L1/L2L1 = 5/3 L2Therefore, Star A is 5/3 = 1.667 times brighter than Star B.

Star a Has an Apparent Magnitude of 5