What is the rate of diffusion in the gas-exchange organ of an air-breathing animal where the area for gas exchange in the lung is 200 mm²,the diffusion constant is 0.08,the PO₂ (partial pressure of oxygen)of the air in the lung is 140 mm Hg,the PO₂ in blood flowing into the lung is 90 mmHg,and the thickness of the gas exchange membrane is 0.001 mm?
A)800,000
B)125
C)00032
D)10,000,000

Question

Quizplus · Accepted Answer

The rate of diffusion can be calculated using Fick's law of diffusion: Rate = (Area × Diffusion constant × (P1 - P2)) / Thickness. Substituting the given values: Rate = (200 mm² × 0.08 × (140 mm Hg - 90 mm Hg)) / 0.001 mm = 800,000.

What Is the Rate of Diffusion in the Gas-Exchange Organ