From which of the following molecules is the hydrolysis of a phosphate most thermodynamically favourable?
A)adenosine-5'-triphosphate
B)glucose phosphate
C)adenosine-5'-diphosphate
D)phosphoenolpyruvate

Question

Quizplus · Accepted Answer

Phosphoenolpyruvate is the most thermodynamically favorable for the hydrolysis of a phosphate because it has a high-energy phosphate bond due to resonance stabilization of the enol form. This makes it a good donor of phosphate groups for biochemical reactions. Adenosine-5'-triphosphate and adenosine-5'-diphosphate also have high-energy phosphate bonds, but their hydrolysis may not be as thermodynamically favorable as phosphoenolpyruvate due to the stabilization provided by the adenine base. Glucose phosphate does not have a high-energy phosphate bond and therefore, hydrolysis of its phosphate is not thermodynamically favorable.

From Which of the Following Molecules Is the Hydrolysis of a Phosphate