The heats of combustion $\left(-\Delta H^{\circ}\right)$ of heptane and 3,3-dimethypentane are 4,817 and $4,809 \mathrm{~kJ} / \mathrm{mol}$, respectively. Which statement is true?

Question

Quizplus · Accepted Answer

The lower the heat of combustion ($-\Delta H^{\circ}$), the more stable the compound. Since 3,3-dimethylpentane has a slightly lower heat of combustion than heptane, it is considered more stable by $8 \mathrm{~kJ} / \mathrm{mol}$.

The Heats of Combustion (−ΔH∘)\left(-\Delta H^{\circ}\right)(−ΔH∘) Of Heptane and 3,3-Dimethypentane Are 4,817 And

The Heats of Combustion $\left(-\Delta H^{\circ}\right)$ Of Heptane and 3,3-Dimethypentane Are 4,817 And