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What Is the Slow, Rate-Determining Step, in the Acid-Catalyzed Dehydration $\beta$

Question 6

Multiple Choice

What is the slow, rate-determining step, in the acid-catalyzed dehydration of 2-methyl-2-propanol?
$What is the slow, rate-determining step, in the acid-catalyzed dehydration of 2-methyl-2-propanol? A) Protonation of the alcohol to form an oxonium ion. B) Loss of water from the oxonium ion to form a carbocation. C) Loss of a \beta -hydrogen from the carbocation to form an alkene. D) The simultaneous loss of a \beta -hydrogen and water from the oxonium ion.$

A) Protonation of the alcohol to form an oxonium ion.
B) Loss of water from the oxonium ion to form a carbocation.
C) Loss of a $\beta$ -hydrogen from the carbocation to form an alkene.
D) The simultaneous loss of a $\beta$ -hydrogen and water from the oxonium ion.