Why can't methanol, $\mathrm{CH}_{3} \mathrm{OH}$, be used as a solvent for sodium amide, $\mathrm{NaNH}_{2}$ ?

Question

Quizplus · Accepted Answer

Sodium amide ($\mathrm{NaNH}_{2}$) is a strong base and methanol ($\mathrm{CH}_{3}\mathrm{OH}$) is a weak acid. When mixed, they undergo an acid-base reaction, where sodium amide deprotonates methanol, forming sodium methoxide ($\mathrm{CH}_{3}\mathrm{O}^{-}\mathrm{Na}^{+}$) and ammonia ($\mathrm{NH}_{3}$). This reaction is incompatible with the use of methanol as a solvent for sodium amide.

Why Can't Methanol CH3OH\mathrm{CH}_{3} \mathrm{OH}CH3​OH , Be Used as a Solvent for Sodium Amide

Why Can't Methanol $\mathrm{CH}_{3} \mathrm{OH}$ , Be Used as a Solvent for Sodium Amide