Calcium carbide, CaC₂, reacts with water to produce calcium hydroxide and acetylene gas, C₂H₂.
CaC₂(s) + 2 H₂O(l) $\rightarrow$ Ca(OH) ₂(aq) + C₂H₂(g)
How many grams of acetylene can be produced from 30.0 g of calcium carbide?

Question

Calcium carbide, CaC₂, reacts with water to produce calcium hydroxide and acetylene gas, C₂H₂.
CaC₂(s) + 2 H₂O(l)

\rightarrow

Ca(OH) ₂(aq) + C₂H₂(g)
How many grams of acetylene can be produced from 30.0 g of calcium carbide?

Quizplus · Accepted Answer

First, we need to calculate the molar mass of calcium carbide (CaC2) which is 40.08 (Ca) + 2*12.01 (C) = 64.10 g/mol. Then, we find the molar mass of acetylene (C2H2) which is 2*12.01 (C) + 2*1.01 (H) = 26.04 g/mol. Given 30.0 g of CaC2, we calculate the moles of CaC2 as 30.0 g / 64.10 g/mol = 0.468 moles. The reaction shows a 1:1 mole ratio between CaC2 and C2H2, so 0.468 moles of CaC2 will produce 0.468 moles of C2H2. Finally, we convert moles of C2H2 to grams: 0.468 moles * 26.04 g/mol = 12.18 g, which rounds to 12.2 g.

Calcium Carbide, CaC2, Reacts with Water to Produce Calcium Hydroxide →\rightarrow→

Calcium Carbide, CaC₂, Reacts with Water to Produce Calcium Hydroxide $\rightarrow$