Suppose the Average Thermal Speed of Molecules in a Gas $\left(22^{\circ} \mathrm{C}\right)$

Suppose the average thermal speed of molecules in a gas at room temperature $\left(22^{\circ} \mathrm{C}\right)$ is $\left|\vec{v}_{0}\right|$ . If we "double" the gas's temperature (to $44^{\circ} \mathrm{C}$ ) , what is the average molecular speed now? Select the closest response.

A) About the same
B)
C)
D)
E)