If each element in this circuit has a resistance of $12 \Omega$, what is the resistance of the entire circuit?
A) $48 \Omega$
B) $32 \Omega$
C) $24 \Omega$
D) $20 \Omega$
E) $12 \Omega$
F) $4 \Omega$
G) Some other value (specify)

Question

Quizplus · Accepted Answer

The circuit's total resistance can be calculated by recognizing it as a combination of series and parallel resistances. First, calculate the parallel part: two $12 \Omega$ resistors in parallel have an equivalent resistance of $R_{parallel} = \frac{1}{\frac{1}{12} + \frac{1}{12}} = 6 \Omega$. Then, add this to the series resistances: $6 \Omega + 12 \Omega + 2 \Omega = 20 \Omega$.

If Each Element in This Circuit Has a Resistance Of 12