Suppose a Baseball Travels $425 \mathrm{ft}(130 \mathrm{~m})$ From Where the Batter Hits It to Where It Lands

Suppose a baseball travels $425 \mathrm{ft}(130 \mathrm{~m})$ from where the batter hits it to where it lands in the stands. The ball's velocity makes an angle of $40^{\circ}$ with respect to the horizontal as the ball leaves the bat. Suppose we first calculate the ball's initial speed ignoring drag and find it to be $\left|\vec{v}_{0}\right|$ . Including drag might plausibly require a higher initial speed for the ball to travel the same horizontal distance. On the other hand, by slowing down the ball's vertical motion, including drag will increase the ball's flight time, allowing the ball the same distance with a slower horizontal velocity. So if we include drag, for the ball to fly the same horizontal distance will we need

A) An initial speed greater than $\left|\vec{v}_{0}\right|$ .
B) An initial speed less than $\left|\vec{v}_{0}\right|$ .
C) An initial speed equal to $\left|\vec{v}_{0}\right|$ .
D) More information to answer for sure.