The ${ }_{2}^{6}$ He nucleus is unstable. To what will it decay?
A) ${ }_{3}^{6} \mathbf{L i}+\boldsymbol{e}^{-}+\bar{v}$
B) ${ }_{3}^{5} \mathrm{Li}+e^{-}+\bar{v}$
C) ${ }_{3}^{6} \mathrm{Li}+\mathrm{e}^{-}+\mathrm{v}$
D) ${ }_{3}^{6} \mathrm{Li}+e^{-}$
E) ${ }_{1}^{5} \mathrm{H}+\mathrm{e}^{+}+\mathrm{V}$

Question

Quizplus · Accepted Answer

The decay of ${ }_{2}^{6}$He nucleus involves beta decay, where a neutron is converted into a proton, an electron ($e^{-}$), and an antineutrino ($\bar{v}$). This increases the atomic number by 1, resulting in a ${ }_{3}^{6}$Li nucleus, while conserving the mass number.

The 26{ }_{2}^{6}26​ He Nucleus Is Unstable 36Li+e−+vˉ{ }_{3}^{6} \mathbf{L i}+\boldsymbol{e}^{-}+\bar{v}36​Li+e−+vˉ B) 35Li+e−+vˉ{ }_{3}^{5} \mathrm{Li}+e^{-}+\bar{v}35​Li+e−+vˉ

The ${ }_{2}^{6}$ He Nucleus Is Unstable ${ }_{3}^{6} \mathbf{L i}+\boldsymbol{e}^{-}+\bar{v}$ B) ${ }_{3}^{5} \mathrm{Li}+e^{-}+\bar{v}$