Suppose we carefully synchronize two identical atomic clocks initially standing next to each other (call them $A$ and $B$ ). We put clock $B$ on a jet plane, which then flies around the world at an essentially constant speed of $300 \mathrm{~m} / \mathrm{s}$, returning $134,000 \mathrm{~s}(37.1 \mathrm{~h})$ later. We then again compare the two clocks. Assume the earth's surface defines an inertial reference frame, and ignore the possible effects of gravity.
-(c) Which clock measures the shorter time interval between the synchronization and comparison events (or do both measure the same time)?
A) Clock A
B) Clock $B$
C) Both
D) Neither

Question

Quizplus · Accepted Answer

Clock B measures the shorter time interval due to time dilation effects as per the theory of relativity. Since clock B is moving at a significant speed relative to clock A, time for clock B slows down compared to clock A, which remains stationary on Earth.

Suppose We Carefully Synchronize Two Identical Atomic Clocks Initially Standing AAA

Suppose We Carefully Synchronize Two Identical Atomic Clocks Initially Standing $A$