As a particle's speed approaches that of light, the difference between its relativistic momentum magnitude $|\vec{p}|$ and its relativistic energy $E$ becomes small (compared to $E$ ).

Name: As a particle's speed approaches that of light, the difference between its relativistic momentum magnitude $|\vec{p}|$ and its relativistic energy $E$ becomes small (compared to $E$ ).
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Quizplus · Accepted Answer

Note that $[E-|\vec{p}|] / E=1-|\vec{v}| \rightarrow 0$ as $|\vec{v}| \rightarrow 1$.

As a Particle's Speed Approaches That of Light, the Difference ∣p⃗∣|\vec{p}|∣p​∣

As a Particle's Speed Approaches That of Light, the Difference $|\vec{p}|$