As temperatures become large, the denominator in equation $\mathrm{T} 4.36$ becomes
Equation $\mathrm{T} 4.36$
$U=3 N E_{\text {avg }}=\frac{3 N \varepsilon e^{-\varepsilon / k_{B} T}}{1-e^{-\varepsilon / k_{B} T}}=\frac{3 N \varepsilon}{e^{\varepsilon / k_{B} T}-1}$
A) very large.
B) very small.
C) approximately 1.
D) approximately -1 .

Question

Quizplus · Accepted Answer

As temperatures become large, the term $\varepsilon / k_{B} T$ in the exponent becomes very small, making $e^{\varepsilon / k_{B} T}$ approach 1. Thus, the denominator $e^{\varepsilon / k_{B} T} - 1$ approaches 0, making it very small.

As Temperatures Become Large, the Denominator in Equation T4.36\mathrm{T} 4.36T4.36 Becomes Equation

As Temperatures Become Large, the Denominator in Equation $\mathrm{T} 4.36$ Becomes
Equation