Reduce to lowest terms. Write your answer without negative exponents: $\frac{3 a^{3}(1-2 b)}{a^{2} b\left(1-4 b+4 b^{2}\right)}$

Name: Reduce to lowest terms. Write your answer without negative exponents: $\frac{3 a^{3}(1-2 b)}{a^{2} b\left(1-4 b+4 b^{2}\right)}$
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The Answer of Reduce to lowest terms. Write your answer without negative exponents: $\frac{3 a^{3}(1-2 b)}{a^{2} b\left(1-4 b+4 b^{2}\right)}$

Reduce to Lowest Terms 3a3(1−2b)a2b(1−4b+4b2)\frac{3 a^{3}(1-2 b)}{a^{2} b\left(1-4 b+4 b^{2}\right)}a2b(1−4b+4b2)3a3(1−2b)​

Reduce to Lowest Terms $\frac{3 a^{3}(1-2 b)}{a^{2} b\left(1-4 b+4 b^{2}\right)}$