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Simplify tan⁡θ+tan⁡50∘1−tan⁡θtan⁡50∘\frac{\tan \theta+\tan 50^{\circ}}{1-\tan \theta \tan 50^{\circ}}

Question 36

Short Answer

Simplify tan⁡θ+tan⁡50∘1−tan⁡θtan⁡50∘\frac{\tan \theta+\tan 50^{\circ}}{1-\tan \theta \tan 50^{\circ}} .

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