Prove that $\tan \theta=\frac{2 \tan \left(\frac{\theta}{2}\right)}{1-\tan^{2}\left(\frac{\theta}{2}\right)}$.

Name: Prove that $\tan \theta=\frac{2 \tan \left(\frac{\theta}{2}\right)}{1-\tan^{2}\left(\frac{\theta}{2}\right)}$.
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The Answer of Prove that $\tan \theta=\frac{2 \tan \left(\frac{\theta}{2}\right)}{1-\tan^{2}\left(\frac{\theta}{2}\right)}$.

Prove That tan⁡θ=2tan⁡(θ2)1−tan⁡2(θ2)\tan \theta=\frac{2 \tan \left(\frac{\theta}{2}\right)}{1-\tan^{2}\left(\frac{\theta}{2}\right)}tanθ=1−tan2(2θ​)2tan(2θ​)​

Prove That $\tan \theta=\frac{2 \tan \left(\frac{\theta}{2}\right)}{1-\tan^{2}\left(\frac{\theta}{2}\right)}$