The power $(\mathrm{W})$ delivered to a load by a $40 \mathrm{~V}$ source with internal resistance of $5 \Omega$ is $P=40 i-5 i^{2}$. What current will give the maximum power?

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The Answer of The power $(\mathrm{W})$ delivered to a load by a $40 \mathrm{~V}$ source with internal resistance of $5 \Omega$ is $P=40 i-5 i^{2}$. What current will give the maximum power?

The Power (W)(\mathrm{W})(W) Delivered to a Load by A 40 V40 \mathrm{~V}40 V Source with Internal Resistance Of

The Power $(\mathrm{W})$ Delivered to a Load by A $40 \mathrm{~V}$ Source with Internal Resistance Of