If 87.5% of a drug is eliminated via first order kinetics in 15 hours. Half-life of this drug is expected to be?

Name: If 87.5% of a drug is eliminated via first order kinetics in 15 hours. Half-life of this drug is expected to be?
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Question

Quizplus · Accepted Answer

In first-order kinetics, the half-life is constant and can be calculated using the formula: t1/2 = (t * ln(2)) / ln(initial concentration/final concentration). Here, 87.5% elimination means 12.5% remains, so the half-life is 15 * ln(2) / ln(1/0.125) = 5 hours.

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