A unit mass of an ideal gas at temperature T undergoes a reversible isothermal process from volume V1 to volume V2 while loosing heat to the surroundings at temperature T in the amount of q. If the gas constant of the gas is R, the entropy change of the gas s during this process is
A) s =R ln(V2/V1) -q/T
B) s = R ln(V2/V1)
C) s =R ln(V1/V2)
D) s =R ln(V1/V2) -q/T
E) s= 0
Correct Answer:
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