Find the product.
-$(x+6 y)(-3 x+8 y)$
A) $x^{2}-10 x y-10 y^{2}$
B) $x^{2}-10 x y+48 y^{2}$
C) $-3 x^{2}-10 x y+48 y^{2}$
D) $-3 x^{2}-10 x y-10 y^{2}$

Question

Quizplus · Accepted Answer

The product is found by distributing each term in the first binomial to each term in the second binomial: $(x)(-3x) + (x)(8y) + (6y)(-3x) + (6y)(8y) = -3x^2 + 8xy - 18xy + 48y^2 = -3x^2 - 10xy + 48y^2$.

Find the Product (x+6y)(−3x+8y)(x+6 y)(-3 x+8 y)(x+6y)(−3x+8y) A) x2−10xy−10y2x^{2}-10 x y-10 y^{2}x2−10xy−10y2

Find the Product $(x+6 y)(-3 x+8 y)$ A) $x^{2}-10 x y-10 y^{2}$