Solve the problem.
-The distance, $s$, in feet, traveled by a body falling freely from rest in $t$ seconds is approximated by the equation $s=16 t^{2}$. An experimenter on a ladder releases a marble from rest. The marble takes 5 seconds to fall to the ground. How high was the marble when it was released?
A) $80 \mathrm{ft}$
B) $400 \mathrm{ft}$
C) $25 \mathrm{ft}$
D) $6400 \mathrm{ft}$

Question

Quizplus · Accepted Answer

The height from which the marble was released can be found by substituting $t = 5$ seconds into the equation $s = 16t^2$. This gives $s = 16 \times 5^2 = 16 \times 25 = 400$ feet.

Solve the Problem sss , in Feet, Traveled by a Body Falling Freely from by a Body

Solve the Problem $s$ , in Feet, Traveled by a Body Falling Freely from by a Body