Factor completely.
-$x^{2}+12 x y+27 y^{2}$
A) $(x-3 y)(x+9 y)$
B) $(x-3 y)(x+y)$
C) $(x+3 y)(x+9 y)$
D) Prime

Name: Factor completely. -$x^{2}+12 x y+27 y^{2}$ A) $(x-3 y)(x+9 y)$ B) $(x-3 y)(x+y)$ C) $(x+3 y)(x+9 y)$ D) Prime
Brand: Quizplus
Rating: 4.9 (35 reviews)

Question

Quizplus · Accepted Answer

The expression $x^{2}+12xy+27y^{2}$ is a quadratic trinomial that can be factored as $(x+3y)(x+9y)$ because the middle term $12xy$ is the sum of the products of the outer and inner terms of the factors, and the last term $27y^2$ is the product of the last terms of the factors.

Factor Completely x2+12xy+27y2x^{2}+12 x y+27 y^{2}x2+12xy+27y2 A) (x−3y)(x+9y)(x-3 y)(x+9 y)(x−3y)(x+9y) B) (x−3y)(x+y)(x-3 y)(x+y)(x−3y)(x+y)

Factor Completely $x^{2}+12 x y+27 y^{2}$ A) $(x-3 y)(x+9 y)$ B) $(x-3 y)(x+y)$