Factor completely.
-$125 p^{3}-1$
A) $(5 p+1)\left(25 p^{2}-5 p+1\right)$
B) $(5 p-1)\left(25 p^{2}+1\right)$
C) $(125 p-1)\left(p^{2}+5 p+1\right)$
D) $(5 p-1)\left(25 p^{2}+5 p+1\right)$

Question

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The Answer of Factor completely.
-$125 p^{3}-1$
A) $(5 p+1)\left(25 p^{2}-5 p+1\right)$
B) $(5 p-1)\left(25 p^{2}+1\right)$
C) $(125 p-1)\left(p^{2}+5 p+1\right)$
D) $(5 p-1)\left(25 p^{2}+5 p+1\right)$

Factor Completely 125p3−1125 p^{3}-1125p3−1 A) (5p+1)(25p2−5p+1)(5 p+1)\left(25 p^{2}-5 p+1\right)(5p+1)(25p2−5p+1) B) (5p−1)(25p2+1)(5 p-1)\left(25 p^{2}+1\right)(5p−1)(25p2+1)

Factor Completely $125 p^{3}-1$ A) $(5 p+1)\left(25 p^{2}-5 p+1\right)$ B) $(5 p-1)\left(25 p^{2}+1\right)$