Solve the problem.
-The time $T$ in seconds for a pendulum of length $L$ feet to make one swing is given by $T=2 \pi \sqrt{\frac{L}{44}}$. How long is a pendulum (to nearest hundredth) if it makes one swing in 1.5 seconds? Use 3.14 for $\pi$.
A) $2.51 \mathrm{ft}$
B) $24.75 \mathrm{ft}$
C) $99 \mathrm{ft}$
D) $15.76 \mathrm{ft}$

Question

Quizplus · Accepted Answer

To find the length $L$, rearrange the formula: $L = \left(\frac{T}{2\pi}\right)^2 \times 44$. Substituting $T = 1.5$ and $\pi = 3.14$, we get $L = \left(\frac{1.5}{2 \times 3.14}\right)^2 \times 44 \approx 2.51$ feet.

Solve the Problem TTT In Seconds for a Pendulum of Length LLL

Solve the Problem $T$ In Seconds for a Pendulum of Length $L$