Solve the formula for the specified variable.
-$\mathrm{F}=\frac{9}{5} \mathrm{C}+32$ for $\mathrm{C}$
A) $C=\frac{5}{F-32}$
B) $\mathrm{C}=\frac{\mathrm{F}-32}{9}$
C) $\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)$
D) $\mathrm{C}=\frac{9}{5}(\mathrm{~F}-32)$

Question

Quizplus · Accepted Answer

To solve for C, subtract 32 from both sides to get $F - 32 = \frac{9}{5}C$. Then multiply both sides by $\frac{5}{9}$ to isolate C, resulting in $C = \frac{5}{9}(F - 32)$.

Solve the Formula for the Specified Variable F=95C+32\mathrm{F}=\frac{9}{5} \mathrm{C}+32F=59​C+32 For C\mathrm{C}C A) C=5F−32C=\frac{5}{F-32}C=F−325​

Solve the Formula for the Specified Variable $\mathrm{F}=\frac{9}{5} \mathrm{C}+32$ For $\mathrm{C}$ A) $C=\frac{5}{F-32}$