Solve the Inequality $\frac{x^{2}+2 x-8}{x^{2}-2 x-48}<0$ A) $(-6,-4)$ Or $(2, \infty)$ B) $(-4,2)$ Or $(8, \infty)$

Solve the inequality.
- $\frac{x^{2}+2 x-8}{x^{2}-2 x-48}<0$

A) $(-6,-4)$ or $(2, \infty)$
B) $(-4,2)$ or $(8, \infty)$
C) $(-\infty,-4)$ or $(-6,8)$
D) $(-6,-4)$ or $(2,8)$