A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 3 pieces of candy at random. Find the probability.
-2 cherry, 1 lemon
A) .3636
B) .1818
C) .1212
D) .7272

Question

Quizplus · Accepted Answer

The probability of drawing 2 cherry and 1 lemon candy is calculated by dividing the number of favorable outcomes by the total number of ways to draw 3 candies. The number of favorable outcomes is the combination of choosing 2 cherries from 6 and 1 lemon from 2, which is (6C2 * 2C1). The total number of ways to draw 3 candies from 11 is 11C3. The probability is (6C2 * 2C1) / 11C3 = 15 * 2 / 165 = 30 / 165 = 0.1818.

A Bag Contains 6 Cherry, 3 Orange, and 2 Lemon