Solve the problem.
-The surface area of a certain mammal, in square meters, is approximated by $A(W, H)=0.29 W^{(0.49)} H^{(0.63)}$, where $\mathrm{W}$ is the weight of the animal in kilograms and $\mathrm{H}$ is the height in meters. Find $\frac{\partial \mathrm{A}}{\partial \mathrm{H}}$.
A) $0.14 \mathrm{~W}^{0.49} \mathrm{H}^{-0.37}$
B) $0.18 \mathrm{~W}^{-0.51} \mathrm{H}^{0.63}$
C) $0.14 \mathrm{~W}-0.51 \mathrm{H} 0.63$
D) $0.18 \mathrm{~W}^{0.49} \mathrm{H}^{-0.37}$

Question

Quizplus · Accepted Answer

Using the product rule, we have:$$\frac{\partial A}{\partial H} = 0.29 W^{0.49} H^{0.63} \cdot 0.63 H^{-0.37} = 0.18 W^{0.49} H^{-0.37}$$

Solve the Problem A(W,H)=0.29W(0.49)H(0.63)A(W, H)=0.29 W^{(0.49)} H^{(0.63)}A(W,H)=0.29W(0.49)H(0.63) , Where W\mathrm{W}W Is the Weight of the Animal in Kilograms And

Solve the Problem $A(W, H)=0.29 W^{(0.49)} H^{(0.63)}$ , Where $\mathrm{W}$ Is the Weight of the Animal in Kilograms And