Consider the experiment of tossing a coin nine times. Find the probability of getting exactly one head.
A) $ \frac{1}{511} $

B) $ \frac{9}{512} $

C) $ \frac{1}{513} $

D) $ \frac{1}{2} $

Question

Consider the experiment of tossing a coin nine times. Find the probability of getting exactly one head. 
A) $ \frac{1}{511} $

B) $ \frac{9}{512} $

C) $ \frac{1}{513} $

D) $ \frac{1}{2} $

Quizplus · Accepted Answer

The probability of getting exactly one head in nine tosses of a fair coin is calculated using the binomial probability formula: $ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} $. Here, $ n = 9 $, $ k = 1 $, and $ p = 0.5 $. So, $ P(X = 1) = \binom{9}{1} (0.5)^1 (0.5)^8 = 9 \times \frac{1}{512} = \frac{9}{512} $.

Consider the Experiment of Tossing a Coin Nine Times 1511 \frac{1}{511} 5111​

Consider the Experiment of Tossing a Coin Nine Times $\frac{1}{511}$