What will the following code display? #include Using namespace std; Void showDub(int); Int main() { $\quad$int x = 2; $\quad$showDub(x); $\quad$cout

Question

What will the following code display?
#include <iostream>
Using namespace std;
Void showDub(int);
Int main()
{
$\quad$int x = 2;
$\quad$showDub(x);
$\quad$cout << x << endl;
$\quad$return 0;
}
void showDub(int num)
{
$\quad$cout << (num * 2) << endl;
}
A) 2
2
B) 4
2
C) 2
4
D) 4
4

Quizplus · Accepted Answer

The function showDub takes an integer as input and outputs its double, which is 4 when called with x=2 in the main function. Then, the value of x is printed using cout, which outputs 2 since the value of x was not changed despite being passed to the showDub function. Therefore, the output will be 4 followed by 2.

What Will the Following Code Display? #Include ≪iostream> Using Namespace \quad

What Will the Following Code Display?
#Include ≪iostream>
Using Namespace $\quad$