Assuming independent assortment for all gene pairs, what is the probability that the following parents, AABbCc × AaBbCc, will produce an AaBbCc offspring?

Question

Quizplus · Accepted Answer

First, we need to determine the possible alleles from each parent:

AABbCc 
Possible alleles: ABc, Abc

AaBbCc 
Possible alleles: ABc, Abc, aBc, abc

To get an AaBbCc offspring, we need to get at least one A from the first parent, one B from either parent, and one C from either parent.

Probability of getting an A from the first parent: 
1 (AA is homozygous dominant)

Probability of getting a B from either parent: 
3/4 (Bb or bB)

Probability of getting a C from either parent: 
3/4 (Cc or cC)

Multiplying these probabilities together gives: 
1 × (3/4) × (3/4) = 9/16

Therefore, the probability of producing an AaBbCc offspring is 9/16, which is answer choice C.

Assuming Independent Assortment for All Gene Pairs, What Is the Probability