If object A is at 400 K and object B is at 800 K,then the radiation intensity of object A will be this amount of that the radiation intensity of object B:

Question

Quizplus · Accepted Answer

The radiation intensity of an object is proportional to the fourth power of its temperature (Stefan-Boltzmann law). Therefore, if object B is at 800 K (twice the temperature of object A, which is at 400 K), the radiation intensity of object A will be (400/800)^4 = 1/16 that of object B.

If Object a Is at 400 K and Object B