For the questions below, use the following skeletal code.
public static void main(String[ ] args)
{
try
{
ExceptionThrowerCode etc = new ExceptionThrowerCode( );
etc.m1( );
etc.m2( );
}
catch (ArithmeticException ae) { ... }
}
public class ExceptionThrowerCode
{
...
public void m1( )
{
...
}
public void m2( )
{
try
{
m3( );
}
catch(ArithmeticException ae) {...}
catch(NullPointerException npe) {...}
}
public void m3( )
{
try
{
...
}
catch(ArithmeticException ae) {...}
}
}
-If a NullPointerException arises in the try statement in m1
A) it is caught in main
B) it is caught in m1
C) it is caught in m2
D) it is caught in m3
E) it is not caught leading to the program terminating

Question

Quizplus · Accepted Answer

E) The method m1 has no catch statements at all, so any exception is propagated to the calling method, main. The method main only has a catch statement for an ArithmeticException, so the NullPointerException is not caught resulting in the program terminating.

For the Questions Below, Use the Following Skeletal Code