The following method lacks a base case.
public int noBaseCase(int x)
{
if (x 0)
return noBaseCase(x - 1) + 1;
else return noBaseCase(x - 2) + 2;
}

Name: The following method lacks a base case. public int noBaseCase(int x) { if (x > 0) return noBaseCase(x - 1) + 1; else return noBaseCase(x - 2) + 2; }
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Question

The following method lacks a base case.
public int noBaseCase(int x)
{
if (x > 0)
return noBaseCase(x - 1) + 1;
else return noBaseCase(x - 2) + 2;
}

Quizplus · Accepted Answer

This method will run infinitely if x is not greater than 0. There is no stopping condition, hence no base case.

The Following Method Lacks a Base Case