Solved

The Following Questions Refer to the Table Below, Which Compares \quad

Question 72

Multiple Choice

The following questions refer to the table below, which compares the % sequence homology of four different parts (2 introns and 2 exons) of a gene that is found in five different eukaryotic species. Each part is numbered to indicate its distance from the promoter (e.g., Intron I is that closest to the promoter) . The data reported for Species A were obtained by comparing DNA from one member of species A to another member of Species A.
\quad \quad \quad \quad \quad \quad \quad  %/ Sequence Homology \text { \%/ Sequence Homology }
 Species  Intron I  Exon I  Intron VI  Exon V  A 100%100%100%100% B 98%99%82%96% C 98%99%89%96%D99%99%92%97%E98%99%80%94%\begin{array} { l l l l l } \text { Species } & \text { Intron I } & \text { Exon I } & \text { Intron VI } & \text { Exon V } \\\text { A } & 100 \% & 100 \% & 100 \% & 100 \% \\\text { B } & 98 \% & 99 \% & 82 \% & 96 \% \\\text { C } & 98 \% & 99 \% & 89 \% & 96 \% \\\mathrm { D } & 99 \% & 99 \% & 92 \% & 97 \% \\\mathrm { E } & 98 \% & 99 \% & 80 \% & 94 \%\end{array}
-Which of these is the best explanation for the relatively low level of sequence homology observed in Intron VI?


A) Mutations that occur here are neutral; thus, are neither selected for nor against, and thereby accumulate over time.
B) Its higher mutation rate has resulted in its highly conserved nature.
C) The occurrence of molecular homoplasy explains it.
D) This intron is not actually homologous, having resulted from separate bacteriophage-induced transduction events in these five species.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents