Given that s is a String, what does the following loop do?
For (int j = s.length( ); j 0; j--)
System.out.print(s.charAt(j-1));
A) it prints s out backwards
B) it prints s out forwards
C) it prints s out backwards after skipping the last character
D) it prints s out backwards but does not print the 0ᵗʰ character
E) it yields a run-time error because there is no character at s.charAt(j-1) for j = 0

Question

Given that s is a String, what does the following loop do?
For (int j = s.length( ); j > 0; j--)
System.out.print(s.charAt(j-1));
A) it prints s out backwards
B) it prints s out forwards
C) it prints s out backwards after skipping the last character
D) it prints s out backwards but does not print the 0ᵗʰ character
E) it yields a run-time error because there is no character at s.charAt(j-1) for j = 0

Quizplus · Accepted Answer

A) The variable j counts down from the length of the String to 1, each time printing out the character at position j-1. The character at length - 1 is the first character printed and this is the last character of the String. It continues until it reaches j = 1, and prints out the character at position j - 1, or the 0ᵗʰ character, so it prints the entire String backwards.

Given That S Is a String, What Does the Following