For the next questions, use the following class definition of a linked list Node:
class Node
{
int info;
Node next;
}
-Assume that head references a linked list although we don't know what is currently stored in that list. Write a block of code using a try-catch block that will work through the entire linked list printing each element out, stopping only when we have reached the end of the list because a NullPointerException is thrown. Once the Exception is thrown, output the number of elements found in the list.
Correct Answer:
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try
{
Node temp = head;
w...
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