In a classroom taste test for PTC the genotype frequency was determined to be P = .35 and Q = .65.After applying the Hardy-Weinberg equation,what was the percentage of genotypes found to be?

Question

Quizplus · Accepted Answer

According to the Hardy-Weinberg equation, the expected genotype frequencies are p^2, 2pq, and q^2, where p is the frequency of one allele and q is the frequency of the other allele. In this case, the frequency of the P allele is 0.35, so the frequency of the p^2 genotype is (0.35)^2 = 0.1225. Similarly, the frequency of the q^2 genotype is (0.65)^2 = 0.4225. Finally, the frequency of the 2pq genotype is 2(0.35)(0.65) = 0.455, which is closest to option B, where p^2 = 0.35, 2pq = 0.00, and q^2 = 0.65.

In a Classroom Taste Test for PTC the Genotype Frequency