Myrmecia pilosula actually consists of several virtually identical,closely related species,with females having chromosome numbers of 18,20,32,48,60,62,and 64.Assume one crossed a female of species (A)with 32 chromosomes and a male of species (B)with 9 chromosomes (males are haploid,and each gamete contains the n complement).How many chromosomes would one expect in the body (somatic)cells of the female offspring?

Question

Quizplus · Accepted Answer

The female parent (A) has 32 chromosomes and the male parent (B) has haploid number of 9 chromosomes, so the total number of chromosomes in the male gamete would be n=9. 
If we assume that the cross results in a female offspring, then it would inherit 16 chromosomes from the mother (half of the diploid number 32) and 9 chromosomes from the father, for a total of 25 chromosomes in the somatic cells of the offspring. Therefore, the correct choice is C.

Myrmecia Pilosula Actually Consists of Several Virtually Identical,closely Related Species,with