The autosomal (not X-linked)gene for brachydactyly,short fingers,is dominant to normal finger length.Assume that a female with brachydactyly in the heterozygous condition is married to a man with normal fingers.What is the probability that
a) their first child will have brachydactyly?
b) their first two children will have brachydactyly?
c) their first child will be a brachydactylous girl?

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The Answer of The autosomal (not X-linked)gene for brachydactyly,short fingers,is dominant to normal finger length.Assume that a female with brachydactyly in the heterozygous condition is married to a man with normal fingers.What is the probability that
a) their first child will have brachydactyly?
b) their first two children will have brachydactyly?
c) their first child will be a brachydactylous girl?

The Autosomal (Not X-Linked)gene for Brachydactyly,short Fingers,is Dominant to Normal