Table 2.1 $${ } _ { 8 } ^ { 16 } \mathrm { O } \quad { } _ { 6 } ^ { 12 } \mathrm { C } \quad { } _ { 1 } ^ { 1 } \mathrm { H }$$
Using the information in Table 2.1,calculate the number of moles in 92 grams of ethanol,C₂H₅OH.

Question

Quizplus · Accepted Answer

The molar mass of ethanol (C₂H₅OH) is calculated as follows: 2*(12.01 g/mol for C) + 6*(1.01 g/mol for H) + 16.00 g/mol for O = 46.07 g/mol. Therefore, 92 grams of ethanol is 92 g / 46.07 g/mol = 2 moles.

Table 21 816O612C11H{ } _ { 8 } ^ { 16 } \mathrm { O } \quad { } _ { 6 } ^ { 12 } \mathrm { C } \quad { } _ { 1 } ^ { 1 } \mathrm { H }816​O612​C11​H

Table 21 ${ } _ { 8 } ^ { 16 } \mathrm { O } \quad { } _ { 6 } ^ { 12 } \mathrm { C } \quad { } _ { 1 } ^ { 1 } \mathrm { H }$