Suppose A and B are independent events where P(A)= 0.42 and P(B)= 0.38.Then,the conditional probability of A,given B,is 0.38.

Question

Quizplus · Accepted Answer

The conditional probability of A given B is defined as P(A|B) = P(A and B)/P(B). Since A and B are assumed to be independent events, P(A and B) = P(A) * P(B) = 0.42 * 0.38 = 0.1596. Therefore, P(A|B) = 0.1596/0.38 = 0.4200, which is not equal to 0.38. Hence, the statement is false.

Suppose a and B Are Independent Events Where P(A)= 0