Suppose that a t test of H₀ : μ₁ - μ₂ = 0 against H₁ : μ₁ - μ₂ ≠ 0 is based on 15 degrees of freedom.If the calculated value of the test statistic is t = -1.75,then the p-value for this test is approximately 0.10.

Question

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If the calculated value of the test statistic t = -1.75 and the test has 15 degrees of freedom, the p-value can be found using a t-distribution table or calculator. With a two-tailed test and a calculated t-value of -1.75, the approximate p-value is 0.0975 or 0.10 (rounded to two decimal places). Therefore, the statement is true.

Suppose That a T Test of H0 : μ1 -

Suppose That a T Test of H₀ : μ₁ -